# Exercise 6.2.6

Show that the worst-case running time of

`MAX-HEAPIFY`

on a heap of size $n$ is $\Omega(\lg{n})$. (Hint: For a heap with $n$ nodes, give node values that cause`MAX-HEAPIFY`

to be called recursively at every node on a simple path from the root down to a leaf.)

This is another obvious one.

Let's take the leftmost path in the given heap. If we put the largest elements
in the heap on that path and the smallest one at the root, `MAX-HEAPIFY`

will
need to be invoked once for each level in the heap in order to push the minimum
element to the leftmost leaf. Since the heap height (and thus the leftmost
path's length) is $\lfloor \lg{n} \rfloor$ (exercise 6.1-2), the worst-case
running time of the procedure is $\Omega(\lg{n})$.